Problem on Train

5. Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A)30 m B)25 m C)27m D)27 7/9 Answer : Option D Explanation: Relative speed = (40 - 20) km/hr = ( 20 x 5/18 ) m/sec = 50/9 m/sec. Therefore Length of faster train = ( 50/9 x 5 ) m = 250/9 m = 27 7/9 m. 6. A train crosses a tree in 120sec, while it crosses a 700m long platform in 190sec. the length of the Train is: A)1200m B)1100m C)1250m D)None of these Answer : Option A Explanation: In 190Sec Cross a 700m Platform I.e., Length of Train + Length of Platform. 190 Sec- 120Sec = 700m 70Sec= 700m Speed= 10 M/Sec In 120 Sec The length wil be 1200m. 7. A train is running at 72 Kmph. It was crossed an electronic pole in 20sec. find the length of the train? A)300 m B)400m C)410m D)405m Answer : Option B Explanation: L = S × T L = 72 Kmph × 20Sec L = 72 × 5/18 × 20 L = 400m 8. A 180m long train is running at 72 Kmph. If it crossed the platform in 20sec. then find the platform Length? A)210m B)230m C)220m D)240m Answer : Option C Explanation: Length = Speed*Time L = 72K.M/H*T L=72*5/18*20 L= 400M. Length of Platform= Length-Length of the Train Length of Platform= 400-180 Length of Platform=220m

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