Problem On Age

6. Age of Father 10 years ago was 3 times the age of her Daughter. After 10 years, Father’s age will be twice that of his Daughter. Find the ratio of their present ages.

A)6:4
B)7:4
C)8:4
D)9:4
Answer : Option B

Explanation:
We given that, age of Father 10 years ago was 3 times the age of her Daughter So, let age of son be x and as Father’s age is 3 times the age of her Daughter, let it be 3x, three years ago. At present: Father’s age will be (3x + 10) and Daughter’s age will be (x + 10) After 10 years: Father’s age will be (3x + 10) +10 and Daughter’s age will be (x + 10) + 10 Father’s age is twice that of Daughter (3x + 10) +10 = 2 [(x + 10) + 10] (3x + 20) = 2[x + 20] Solving the equation, we get x = 20 We are asked to find the present ratio. (3x + 10) : (x + 10) = 70 : 30 = 7 : 3

7. A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 32 now, the son age 4 years back was :

A)14
B)16
C)12
D)10
Answer : Option C

Explanation:
Let the son's present age be x years .Then, (32 - x) = x x= 16. Son's age 4 years back = (16 - 4) = 12 years

8. Five years ago, the average age of Ram, Hari, Jadu and Madhu was 45 years. With Sita Joining them now, the average of all the five is 49 years. The age of Sita is?

A)46
B)44
C)45
D)42
Answer : Option C

Explanation:
5 years ago average age of Ram, Hari, Jadu and Madhu = 45 years 5 years ago total age of Ram, Hari, Jadu and Madhu = 45 x 4 = 180 years Total present age of Ram, Hari, Jadu and Madhu = 180 + 5x4 = 200 years If Sita's present age is x years =>(200+x)/5=49 x=45years

9. In 12 years, Lipu will be twice as old as Jhili was 12 years ago. If Lipu is now 6 years older than Jhili, the present age of Jhili is :

A)46
B)44
C)45
D)42
Answer : Option D

Explanation:
Let Jhili's present age = x years. Then, Lipu's present age = (x + 6) years. (x + 6) + 12 = 2(x - 12) => x + 18 = 2x - 24 => x =42.

10. The ratio of the present ages of P and Q is 3 : 4. Five years ago, the ratio of their ages was 5 : 7. Find their present ages.

A)30,40
B)40,30
C)40,50
D)50,40
Answer : Option A

Explanation:
As the ratio of their present ages is 3 : 4 , let their present ages be 3X and 4X. So, 5 years ago, as the ratio of their ages was 5 : 7, we can write (3x-5) : (4x-5) = 5 : 7. Solving, we get X = 10. Hence, their present ages are 3X = 30 and 4X = 40



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